Select the correct answer.

The cost to rent a car at one agency is [tex]$\$[/tex]24.50[tex]$ per day plus an additional $[/tex]\[tex]$15.99$[/tex] fee for insurance. At a different agency, the cost to rent a car is [tex]$\$[/tex]27.50[tex]$ per day, but the insurance is only an additional $[/tex]\[tex]$3.99$[/tex] fee. Which equation could be used to find the number of days, [tex]$d$[/tex], at which the rental fee is the same for both agencies?

A. [tex]$24.5d + 15.99 = 27.5d + 3.99$[/tex]

B. [tex]$24.5 + 15.99d = 27.5 + 3.99d$[/tex]

C. [tex]$40.49d = 31.49d$[/tex]

D. [tex]$27.5d + 15.99 = 24.5d + 3.99$[/tex]



Answer :

To find the number of days [tex]\( d \)[/tex] at which the rental fee is the same for both agencies, we need to set up equations for the total cost of renting a car for each agency and then set these equations equal to each other.

### Agency 1

The cost per day is \[tex]$24.50, and there is an additional insurance fee of \$[/tex]15.99. Therefore, the total cost for renting the car from Agency 1 for [tex]\( d \)[/tex] days is:

[tex]\[ \text{Total Cost}_1 = 24.5d + 15.99 \][/tex]

### Agency 2

The cost per day is \[tex]$27.50, and there is an additional insurance fee of \$[/tex]3.99. Therefore, the total cost for renting the car from Agency 2 for [tex]\( d \)[/tex] days is:

[tex]\[ \text{Total Cost}_2 = 27.5d + 3.99 \][/tex]

To find the number of days [tex]\( d \)[/tex] at which the rental fees are equal for both agencies, set the two total cost equations equal to each other:

[tex]\[ 24.5d + 15.99 = 27.5d + 3.99 \][/tex]

Thus, the correct equation is:

[tex]\[ \boxed{24.5d + 15.99 = 27.5d + 3.99} \][/tex]

So, the correct answer is:

[tex]\[ \text{A. } 24.5d + 15.99 = 27.5d + 3.99 \][/tex]