Answer :
To prove that the diagonals of square PQRS are perpendicular bisectors of each other, we need to verify two main points:
1. The diagonals are perpendicular to each other.
2. The diagonals bisect each other.
### Step 1: Checking Perpendicularity of Diagonals
To determine if two lines are perpendicular, the product of their slopes should be -1.
- Given the slopes of the diagonals [tex]\( \overline{RP} \)[/tex] and [tex]\( \overline{SQ} \)[/tex]:
- Slope of [tex]\( \overline{RP} \)[/tex] is 7
- Slope of [tex]\( \overline{SQ} \)[/tex] is [tex]\( -\frac{1}{7} \)[/tex]
Calculate their product:
[tex]\[ \text{slope\_product} = 7 \times \left(-\frac{1}{7}\right) = -1 \][/tex]
Since the product of the slopes is -1, the diagonals [tex]\( \overline{RP} \)[/tex] and [tex]\( \overline{SQ} \)[/tex] are perpendicular.
### Step 2: Checking Bisecting Property of Diagonals
For the diagonals to bisect each other, they must intersect at their midpoint. The given information tells us:
- The midpoint of both diagonals is [tex]\( \left(4 \frac{1}{2}, 5 \frac{1}{2}\right) \)[/tex].
This midpoint is common to both [tex]\( \overline{RP} \)[/tex] and [tex]\( \overline{SQ} \)[/tex]. Therefore, the diagonals bisect each other at this point.
### Conclusion
1. Perpendicularity: The product of the slopes of diagonals [tex]\( \overline{RP} \)[/tex] and [tex]\( \overline{SQ} \)[/tex] is -1, indicating they are perpendicular.
2. Bisecting at Midpoint: Both diagonals share a common midpoint at [tex]\( \left(4 \frac{1}{2}, 5 \frac{1}{2}\right) \)[/tex], indicating they bisect each other.
Thus, these two points confirm that the diagonals of square PQRS are perpendicular bisectors of each other.
1. The diagonals are perpendicular to each other.
2. The diagonals bisect each other.
### Step 1: Checking Perpendicularity of Diagonals
To determine if two lines are perpendicular, the product of their slopes should be -1.
- Given the slopes of the diagonals [tex]\( \overline{RP} \)[/tex] and [tex]\( \overline{SQ} \)[/tex]:
- Slope of [tex]\( \overline{RP} \)[/tex] is 7
- Slope of [tex]\( \overline{SQ} \)[/tex] is [tex]\( -\frac{1}{7} \)[/tex]
Calculate their product:
[tex]\[ \text{slope\_product} = 7 \times \left(-\frac{1}{7}\right) = -1 \][/tex]
Since the product of the slopes is -1, the diagonals [tex]\( \overline{RP} \)[/tex] and [tex]\( \overline{SQ} \)[/tex] are perpendicular.
### Step 2: Checking Bisecting Property of Diagonals
For the diagonals to bisect each other, they must intersect at their midpoint. The given information tells us:
- The midpoint of both diagonals is [tex]\( \left(4 \frac{1}{2}, 5 \frac{1}{2}\right) \)[/tex].
This midpoint is common to both [tex]\( \overline{RP} \)[/tex] and [tex]\( \overline{SQ} \)[/tex]. Therefore, the diagonals bisect each other at this point.
### Conclusion
1. Perpendicularity: The product of the slopes of diagonals [tex]\( \overline{RP} \)[/tex] and [tex]\( \overline{SQ} \)[/tex] is -1, indicating they are perpendicular.
2. Bisecting at Midpoint: Both diagonals share a common midpoint at [tex]\( \left(4 \frac{1}{2}, 5 \frac{1}{2}\right) \)[/tex], indicating they bisect each other.
Thus, these two points confirm that the diagonals of square PQRS are perpendicular bisectors of each other.