Pre-Test

1. If [tex]$f(x)$[/tex] and [tex]$f^{-1}(x)$[/tex] are inverse functions of each other and [tex][tex]$f(x) = 2x + 5$[/tex][/tex], what is [tex]$f^{-1}(8)$[/tex]?

A. [tex]-1[/tex]
B. [tex]\frac{3}{2}[/tex]
C. [tex]\frac{41}{8}[/tex]
D. [tex]23[/tex]



Answer :

To find [tex]\( f^{-1}(8) \)[/tex], we first need to determine the inverse function [tex]\( f^{-1}(x) \)[/tex] of the given function [tex]\( f(x) = 2x + 5 \)[/tex].

Here are the detailed steps to find the inverse function:

1. Set up the equation:
We start with the function [tex]\( f(x) = 2x + 5 \)[/tex] and replace [tex]\( f(x) \)[/tex] with [tex]\( y \)[/tex]:
[tex]\[ y = 2x + 5 \][/tex]

2. Swap variables:
To find the inverse, we switch [tex]\( x \)[/tex] and [tex]\( y \)[/tex]:
[tex]\[ x = 2y + 5 \][/tex]

3. Solve for [tex]\( y \)[/tex]:
To isolate [tex]\( y \)[/tex], we follow these steps:
[tex]\[ x - 5 = 2y \][/tex]
[tex]\[ y = \frac{x - 5}{2} \][/tex]

Therefore, the inverse function is:
[tex]\[ f^{-1}(x) = \frac{x - 5}{2} \][/tex]

4. Evaluate [tex]\( f^{-1}(8) \)[/tex]:
We substitute [tex]\( x = 8 \)[/tex] into the inverse function:
[tex]\[ f^{-1}(8) = \frac{8 - 5}{2} \][/tex]
[tex]\[ f^{-1}(8) = \frac{3}{2} \][/tex]

So, [tex]\( f^{-1}(8) = \frac{3}{2} \)[/tex].

Thus, the correct answer is:
[tex]\[ \boxed{\frac{3}{2}} \][/tex]