Consider the system of equations shown.

[tex]\[
\begin{cases}
y = x + 11 \\
-y = -x + 11
\end{cases}
\][/tex]

What is the solution to this system of equations?

A. [tex]$(0, 11)$[/tex]

B. [tex]$(0, -11)$[/tex]

C. no solution

D. infinitely many solutions



Answer :

To solve the given system of equations:
[tex]\[ \left\{ \begin{array}{c} y = x + 11 \\ -y = -x + 11 \end{array} \right. \][/tex]

Let's simplify the second equation to make it more comparable to the first. Simplifying [tex]\(-y = -x + 11\)[/tex] results in:
[tex]\[ y = x - 11 \][/tex]

Now we have the following system of equations:
[tex]\[ \left\{ \begin{array}{c} y = x + 11 \\ y = x - 11 \end{array} \right. \][/tex]

To find the solution, we set the right-hand sides of the equations equal to each other:
[tex]\[ x + 11 = x - 11 \][/tex]

Subtracting [tex]\(x\)[/tex] from both sides, we get:
[tex]\[ 11 = -11 \][/tex]

This statement is a contradiction and is never true. This means there is no value of [tex]\(x\)[/tex] that can satisfy both equations simultaneously.

Therefore, there is no solution to this system of equations. The correct answer is:

no solution