Answer:
(a) 2
Step-by-step explanation:
Using the property of logarithms
• [tex]log_{b}[/tex] x = n ⇒ x = [tex]b^{n}[/tex]
Using the property of exponents
• [tex]a^{n}[/tex] ⇔ [tex]\frac{1}{a^{-n} }[/tex]
given
[tex]log_{\frac{1}{2} }[/tex] x = - 1 , then
x = [tex](\frac{1}{2}) ^{-1}[/tex] = [tex]\frac{1}{2^{-1} }[/tex] = [tex]2^{1}[/tex] = 2
