Answer :
To write the total ionic equation and the net ionic equation for the reaction between hydrogen cyanide ([tex]\(HCN\)[/tex]) and lithium hydroxide ([tex]\(LiOH\)[/tex]), follow these steps:
### Total Ionic Equation:
1. Dissociation of Reactants: HCN is a weak acid and partially dissociates into [tex]\(H^+\)[/tex] and [tex]\(CN^-\)[/tex]. LiOH is a strong base and fully dissociates into [tex]\(Li^+\)[/tex] and [tex]\(OH^-\)[/tex].
[tex]\[ HCN \rightarrow H^+ + CN^- \][/tex]
[tex]\[ LiOH \rightarrow Li^+ + OH^- \][/tex]
When combined, the total ionic equation includes all ions present in the reaction mixture:
[tex]\[ H^+ + CN^- + Li^+ + OH^- \rightarrow Li^+ + CN^- + H_2O \][/tex]
2. Formation of Products: [tex]\(H^+\)[/tex] reacts with [tex]\(OH^-\)[/tex] to form water ([tex]\(H_2O\)[/tex]), while [tex]\(Li^+\)[/tex] and [tex]\(CN^-\)[/tex] remain unchanged as spectators.
[tex]\[ H^+ + OH^- \rightarrow H_2O \][/tex]
### Net Ionic Equation:
To find the net ionic equation, we eliminate the spectator ions from the total ionic equation. The spectator ions in this reaction are [tex]\(Li^+\)[/tex] and [tex]\(CN^-\)[/tex], as they do not participate in the formation of the final product (water).
Removing the spectator ions, we obtain the net ionic equation:
[tex]\[ H^+ + OH^- \rightarrow H_2O \][/tex]
### Summary:
- Total Ionic Equation:
[tex]\[ H^+ + CN^- + Li^+ + OH^- \rightarrow Li^+ + CN^- + H_2O \][/tex]
- Net Ionic Equation:
[tex]\[ H^+ + OH^- \rightarrow H_2O \][/tex]
### Total Ionic Equation:
1. Dissociation of Reactants: HCN is a weak acid and partially dissociates into [tex]\(H^+\)[/tex] and [tex]\(CN^-\)[/tex]. LiOH is a strong base and fully dissociates into [tex]\(Li^+\)[/tex] and [tex]\(OH^-\)[/tex].
[tex]\[ HCN \rightarrow H^+ + CN^- \][/tex]
[tex]\[ LiOH \rightarrow Li^+ + OH^- \][/tex]
When combined, the total ionic equation includes all ions present in the reaction mixture:
[tex]\[ H^+ + CN^- + Li^+ + OH^- \rightarrow Li^+ + CN^- + H_2O \][/tex]
2. Formation of Products: [tex]\(H^+\)[/tex] reacts with [tex]\(OH^-\)[/tex] to form water ([tex]\(H_2O\)[/tex]), while [tex]\(Li^+\)[/tex] and [tex]\(CN^-\)[/tex] remain unchanged as spectators.
[tex]\[ H^+ + OH^- \rightarrow H_2O \][/tex]
### Net Ionic Equation:
To find the net ionic equation, we eliminate the spectator ions from the total ionic equation. The spectator ions in this reaction are [tex]\(Li^+\)[/tex] and [tex]\(CN^-\)[/tex], as they do not participate in the formation of the final product (water).
Removing the spectator ions, we obtain the net ionic equation:
[tex]\[ H^+ + OH^- \rightarrow H_2O \][/tex]
### Summary:
- Total Ionic Equation:
[tex]\[ H^+ + CN^- + Li^+ + OH^- \rightarrow Li^+ + CN^- + H_2O \][/tex]
- Net Ionic Equation:
[tex]\[ H^+ + OH^- \rightarrow H_2O \][/tex]