To determine which reaction yields a neutral salt, we need to identify a reaction between a strong acid and a strong base. When such a reaction occurs, it typically results in a neutral salt and water.
Step-by-Step Solution:
1. Identify the Reagents in Each Reaction:
- Reaction 1: [tex]\(2 \, \text{NaOH} + \text{H}_2\text{SO}_4\)[/tex]
- [tex]\( \text{NaOH} \)[/tex] is a strong base.
- [tex]\( \text{H}_2\text{SO}_4 \)[/tex] is a strong acid.
- Reaction 2: [tex]\( \text{NaOH} + \text{HCN} \)[/tex]
- [tex]\( \text{NaOH} \)[/tex] is a strong base.
- [tex]\( \text{HCN} \)[/tex] is a weak acid.
- Reaction 3: [tex]\( \text{KOH} + \text{HF} \)[/tex]
- [tex]\( \text{KOH} \)[/tex] is a strong base.
- [tex]\( \text{HF} \)[/tex] is a weak acid.
- Reaction 4: [tex]\(2 \, \text{NH}_4\text{OH} + \text{H}_2\text{SO}_4\)[/tex]
- [tex]\( \text{NH}_4\text{OH} \)[/tex] is a weak base.
- [tex]\( \text{H}_2\text{SO}_4 \)[/tex] is a strong acid.
2. Determine the Nature of Each Reaction:
- Reaction 1 involves a strong base ([tex]\( \text{NaOH} \)[/tex]) and a strong acid ([tex]\( \text{H}_2\text{SO}_4 \)[/tex]). This combination should yield a neutral salt.
- Reaction 2 involves a strong base ([tex]\( \text{NaOH} \)[/tex]) and a weak acid ([tex]\( \text{HCN} \)[/tex]). This combination does not yield a neutral salt.
- Reaction 3 involves a strong base ([tex]\( \text{KOH} \)[/tex]) and a weak acid ([tex]\( \text{HF} \)[/tex]). This combination does not yield a neutral salt.
- Reaction 4 involves a weak base ([tex]\( \text{NH}_4\text{OH} \)[/tex]) and a strong acid ([tex]\( \text{H}_2\text{SO}_4 \)[/tex]). This combination does not yield a neutral salt.
3. Conclusion:
Since only Reaction 1 involves a strong acid and a strong base, it is the reaction that will yield a neutral salt.
Therefore, the reaction that yields a neutral salt is:
[tex]\[ 2 \, \text{NaOH} + \text{H}_2\text{SO}_4 \][/tex]
Thus, the correct answer is the first reaction.
