Find the distance between the two points, rounding to the nearest tenth if necessary.

Points: [tex](5, -8) \text{ and } (-3, -1)[/tex]

Submit your answer: [tex]$\square$[/tex]



Answer :

To find the distance between the two points [tex]\((5, -8)\)[/tex] and [tex]\((-3, -1)\)[/tex], we will use the distance formula, which is:

[tex]\[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \][/tex]

Given points:

- [tex]\((x_1, y_1) = (5, -8)\)[/tex]
- [tex]\((x_2, y_2) = (-3, -1)\)[/tex]

Step-by-step solution:

1. Calculate the differences between the x-coordinates and y-coordinates:
[tex]\[ x_2 - x_1 = -3 - 5 = -8 \][/tex]
[tex]\[ y_2 - y_1 = -1 - (-8) = -1 + 8 = 7 \][/tex]

2. Square these differences:
[tex]\[ (x_2 - x_1)^2 = (-8)^2 = 64 \][/tex]
[tex]\[ (y_2 - y_1)^2 = 7^2 = 49 \][/tex]

3. Sum the squared differences:
[tex]\[ (x_2 - x_1)^2 + (y_2 - y_1)^2 = 64 + 49 = 113 \][/tex]

4. Take the square root of the sum to find the distance:
[tex]\[ d = \sqrt{113} \approx 10.63014581273465 \][/tex]

5. Round the distance to the nearest tenth:
[tex]\[ d \approx 10.6 \][/tex]

Therefore, the distance between the points [tex]\((5, -8)\)[/tex] and [tex]\((-3, -1)\)[/tex], rounded to the nearest tenth, is [tex]\(10.6\)[/tex].