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A triangular piece of rubber is stretched equally from all sides, without distorting its shape, such that each side of the enlarged triangle is twice the length of the original side.

The area of the triangle _______ to _______ times the original area.

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Answer :

To solve the problem of determining how the area of a triangle changes when its side lengths are doubled, we can follow these steps:

1. Understand the relationship between side length and area:
- When a geometric shape such as a triangle is enlarged by scaling its sides uniformly, its area changes according to the square of the scaling factor.

2. Identify the scaling factor:
- The problem states that each side of the triangle is doubled. Thus, the scaling factor is 2.

3. Apply the scaling factor to the area:
- If the original area of the triangle is [tex]\( A \)[/tex], then the area of the enlarged triangle is calculated by multiplying [tex]\( A \)[/tex] by the square of the scaling factor. This is written mathematically as:
[tex]\[ \text{new area} = A \times (\text{scale factor})^2 \][/tex]

4. Calculate the new area:
- Given the scale factor is 2, we substitute this value into the formula:
[tex]\[ \text{new area} = A \times (2)^2 = A \times 4 \][/tex]

5. Determine the ratio of the new area to the original area:
- The new area is 4 times the original area. Therefore, if the original area is 1 unit, the new area would be 4 units.

So, when the side lengths of a triangular piece of rubber are stretched to twice their original lengths, the area of the triangle becomes 4 times the original area.

Thus, the correct answer is:
"The area of the triangle increases to 4 times the original area."