Select the correct answer.

The volume of helium in a blimp is [tex]$6.28 \times 10^9$[/tex] milliliters. The density of helium in the blimp is [tex]0.1786 \frac{\text{kg}}{\text{m}^3}[/tex]. Find the mass of the helium in the blimp. (Hint: [tex]1,000 \text{ L} = 1[/tex] cubic meter)

A. [tex]1,120 \text{ kg}[/tex]

B. [tex]112 \text{ kg}[/tex]

C. [tex]352 \times 10^7 \text{ kg}[/tex]

D. [tex]28040 \text{ kg}[/tex]



Answer :

To find the mass of helium in the blimp, we need to follow these steps:

### Step 1: Convert the Volume from Milliliters to Cubic Meters
The volume of helium given is [tex]\(6.28 \times 10^9\)[/tex] milliliters (ml). Since [tex]\(1,000,000\)[/tex] milliliters equal [tex]\(1\)[/tex] cubic meter ([tex]\(1,000 L = 1 m^3\)[/tex]), we can convert the volume of helium to cubic meters.

[tex]\[ \text{Volume in cubic meters} = \frac{6.28 \times 10^9 \text{ ml}}{1,000,000} = 6.28 \times 10^3 \text{ cubic meters} = 6280 \text{ cubic meters} \][/tex]

### Step 2: Calculate the Mass Using the Density
The density of helium is [tex]\(0.1786 \frac{\text{kg}}{\text{m}^3}\)[/tex]. To find the mass, we use the formula:

[tex]\[ \text{Mass} = \text{Volume} \times \text{Density} \][/tex]

[tex]\[ \text{Mass} = 6280 \text{ cubic meters} \times 0.1786 \frac{\text{kg}}{\text{cubic meter}} = 1121.608 \text{ kg} \][/tex]

### Step 3: Compare the Calculated Mass with Given Options
Let's compare the calculated mass of [tex]\(1121.608 \text{ kg}\)[/tex] with the provided options:

- Option A: [tex]\(1,120 \text{ kg}\)[/tex]
- Option R: [tex]\(112\)[/tex]
- Option C: [tex]\(352 \times 10^7 \text{ kg} = 3520000000 \text{ kg}\)[/tex]
- Option D: [tex]\(28040 \text{ hg} = 2804 \text{ kg}\)[/tex] (since 1 hectogram (hg) = 0.1 kg)

By comparing the choices, it is evident that the option [tex]\(1,120 \text{ kg}\)[/tex] is the closest to our calculated mass of [tex]\(1121.608 \text{ kg}\)[/tex].

### Conclusion
The correct answer is:

A. 1120 kg