Answer :

Sure, let's find [tex]\( f(x) \)[/tex] and [tex]\( f(0) \)[/tex] given the functional equation [tex]\( f(x+2) = 2x + 1 \)[/tex].

### Step-by-Step Solution:

1. Assume the Form of [tex]\( f(x) \)[/tex]:
We start by assuming that [tex]\( f(x) \)[/tex] is a linear function, since the given functional equation [tex]\( f(x+2) = 2x + 1 \)[/tex] suggests linearity. Let:
[tex]\[ f(x) = ax + b \][/tex]

2. Substitute [tex]\( x+2 \)[/tex] into the Assumed Form:
Substitute [tex]\( x + 2 \)[/tex] into the assumed form of [tex]\( f(x) \)[/tex]:
[tex]\[ f(x+2) = a(x+2) + b \][/tex]
[tex]\[ f(x+2) = ax + 2a + b \][/tex]

3. Set Up the Equation Using the Given Functional Equation:
According to the problem statement, [tex]\( f(x+2) = 2x + 1 \)[/tex]. So, equate the two expressions for [tex]\( f(x+2) \)[/tex]:
[tex]\[ ax + 2a + b = 2x + 1 \][/tex]

4. Solve for [tex]\( a \)[/tex] and [tex]\( b \)[/tex]:
For the above equation to hold for all [tex]\( x \)[/tex], the coefficients of [tex]\( x \)[/tex] and the constant terms on both sides must be equal. Therefore, we get two separate equations:
[tex]\[ a = 2 \][/tex]
[tex]\[ 2a + b = 1 \][/tex]
Substitute [tex]\( a = 2 \)[/tex] into the second equation:
[tex]\[ 2(2) + b = 1 \][/tex]
[tex]\[ 4 + b = 1 \][/tex]
[tex]\[ b = 1 - 4 \][/tex]
[tex]\[ b = -3 \][/tex]

5. Formulate [tex]\( f(x) \)[/tex] Using the Values of [tex]\( a \)[/tex] and [tex]\( b \)[/tex]:
Now that we have [tex]\( a = 2 \)[/tex] and [tex]\( b = -3 \)[/tex], we can write:
[tex]\[ f(x) = 2x - 3 \][/tex]

6. Find [tex]\( f(0) \)[/tex]:
Finally, substitute [tex]\( x = 0 \)[/tex] into [tex]\( f(x) \)[/tex] to find [tex]\( f(0) \)[/tex]:
[tex]\[ f(0) = 2(0) - 3 \][/tex]
[tex]\[ f(0) = -3 \][/tex]

### Summary:
- The function [tex]\( f(x) \)[/tex] is [tex]\( 2x - 3 \)[/tex].
- The value of [tex]\( f(0) \)[/tex] is [tex]\( -3 \)[/tex].

Thus, [tex]\( f(x) = 2x - 3 \)[/tex] and [tex]\( f(0) = -3 \)[/tex].