To find the temperature of the flame in degrees Celsius when the temperature in Kelvin is given, we use the conversion formula:
[tex]\[ K = {}^\circ C + 273.15 \][/tex]
Given:
[tex]\[ K = 1376.06 \][/tex]
We need to solve for [tex]${}^\circ C$[/tex] (degrees Celsius). Rearranging the formula, we get:
[tex]\[ {}^\circ C = K - 273.15 \][/tex]
Substituting the given value of [tex]\( K \)[/tex]:
[tex]\[ {}^\circ C = 1376.06 - 273.15 \][/tex]
Perform the subtraction:
[tex]\[ {}^\circ C = 1102.91 \][/tex]
Therefore, the temperature of the flame in degrees Celsius is:
[tex]\[ \boxed{1102.91} \][/tex]
Expressed to six significant figures, it is:
[tex]\[ \boxed{1102.91} \][/tex]
