Find the equation of the axis of symmetry of the following parabola algebraically.

[tex]\[ y = 3x^2 + 24x + 42 \][/tex]

Answer Attempt 1 out of 2

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Answer :

Sure! To find the axis of symmetry for the given quadratic equation [tex]\(y = 3x^2 + 24x + 42\)[/tex], we can follow these steps:

1. A quadratic equation in the standard form is given by [tex]\(y = ax^2 + bx + c\)[/tex]. In this case, we have:
[tex]\[ a = 3, \quad b = 24, \quad \text{and} \quad c = 42 \][/tex]

2. The formula to determine the axis of symmetry for a quadratic equation is:
[tex]\[ x = -\frac{b}{2a} \][/tex]

3. Substitute the values of [tex]\(a\)[/tex] and [tex]\(b\)[/tex] into the formula:
[tex]\[ x = -\frac{24}{2 \cdot 3} \][/tex]

4. Perform the arithmetic operations inside the fraction:
[tex]\[ x = -\frac{24}{6} \][/tex]

5. Simplify the fraction:
[tex]\[ x = -4 \][/tex]

So, the equation of the axis of symmetry for the given parabola [tex]\(y = 3x^2 + 24x + 42\)[/tex] is:
[tex]\[ x = -4 \][/tex]

Therefore, the axis of symmetry is [tex]\(x = -4\)[/tex].