Enter the number that belongs in the box as you solve the equation.

[tex]\[
\begin{array}{rcl}
5x - 2 &=& 4 + 2x \\
-2x \quad & & \quad -2x \\
\hline
3x - 2 &=& 4 \\
+2 \quad & & \quad +2 \\
\hline
3x &=& 6 \\
\end{array}
\][/tex]

[tex]\[
\frac{3x}{?} = \frac{6}{?}
\][/tex]



Answer :

Let's solve the equation step by step to determine the number that belongs in the box:

1. Starting with the equation:
[tex]\[ 5x - 2 = 4 + 2x \][/tex]

2. Subtract [tex]\(2x\)[/tex] from both sides to collect all terms involving [tex]\(x\)[/tex] on one side:
[tex]\[ (5x - 2) - 2x = (4 + 2x) - 2x \][/tex]
Simplifying this, you get:
[tex]\[ 3x - 2 = 4 \][/tex]

3. Add 2 to both sides to isolate the term with [tex]\(x\)[/tex]:
[tex]\[ (3x - 2) + 2 = 4 + 2 \][/tex]
Simplifying this, you get:
[tex]\[ 3x = 6 \][/tex]

4. Divide both sides by 3 to solve for [tex]\(x\)[/tex]:
[tex]\[ \frac{3x}{3} = \frac{6}{3} \][/tex]
Simplifying this, you get:
[tex]\[ x = 2 \][/tex]

The number that belongs in the box is [tex]\(3\)[/tex].