A garden is in the shape of a semicircle with a diameter of 38 m. What is the area of the garden? (Take [tex]$\pi = 3.14$[/tex]. Your answer will be numerical only and rounded to the nearest tenth.)

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Answer :

To determine the area of a garden that is in the shape of a semicircle with a diameter of 38 meters, we will follow these steps:

1. Calculate the radius of the semicircle:
The radius [tex]\( r \)[/tex] of a circle is half of its diameter. Given that the diameter is 38 meters, we calculate the radius as:
[tex]\[ r = \frac{38}{2} = 19 \text{ meters} \][/tex]

2. Calculate the area of the full circle:
The area [tex]\( A \)[/tex] of a full circle is given by the formula:
[tex]\[ A = \pi r^2 \][/tex]
Substituting the given value of [tex]\(\pi = 3.14\)[/tex] and the calculated radius [tex]\( r = 19 \)[/tex]:
[tex]\[ A = 3.14 \times (19)^2 = 3.14 \times 361 = 1133.54 \text{ square meters} \][/tex]

3. Calculate the area of the semicircle:
A semicircle is half of a full circle. Therefore, the area of the semicircle is:
[tex]\[ \text{Area of semicircle} = \frac{1133.54}{2} = 566.77 \text{ square meters} \][/tex]

4. Round the result to the nearest tenth:
The area of the semicircle, rounded to the nearest tenth, is:
[tex]\[ 566.8 \text{ square meters} \][/tex]

Therefore, the area of the garden rounded to the nearest tenth is:

Answer: 566.8