To solve the problem of calculating the product of [tex]\( \frac{8}{15} \)[/tex], [tex]\( \frac{6}{5} \)[/tex], and [tex]\( \frac{1}{3} \)[/tex], you can follow these steps:
1. Multiply the numerators (the top parts of the fractions) together:
[tex]\[ 8 \times 6 \times 1 = 48 \][/tex]
2. Multiply the denominators (the bottom parts of the fractions) together:
[tex]\[ 15 \times 5 \times 3 = 225 \][/tex]
3. Form the new fraction by putting the product of the numerators over the product of the denominators:
[tex]\[ \frac{48}{225} \][/tex]
4. Simplify the fraction if possible:
Both 48 and 225 have a common factor of 3.
[tex]\[ \frac{48 \div 3}{225 \div 3} = \frac{16}{75} \][/tex]
Thus, the answer is:
C. [tex]\( \frac{16}{75} \)[/tex]
