How much money will a borrower using Loan 2 pay in interest over the life of the loan?

\begin{tabular}{|l|r|r|}
\hline & \multicolumn{1}{|c|}{Loan 1} & \multicolumn{1}{c|}{Loan 2} \\
\hline Principal & [tex]$\$[/tex]5800.00[tex]$ & $[/tex]\[tex]$5800.00$[/tex] \\
\hline Monthly Payment & [tex]$\$[/tex]254.00[tex]$ & $[/tex]\[tex]$183.00$[/tex] \\
\hline Duration & 24 months & 36 months \\
\hline
\end{tabular}



Answer :

To determine how much interest the borrower will pay over the life of Loan 2, we'll follow these steps:

1. Identify the principal amount (initial loan amount): The principal amount for Loan 2 is \[tex]$5800.00. 2. Identify the monthly payment: The monthly payment for Loan 2 is \$[/tex]183.00.

3. Identify the duration of the loan: The loan duration for Loan 2 is 36 months.

4. Calculate the total payment amount made over the life of the loan: This is done by multiplying the monthly payment by the number of months.
[tex]\[ \text{Total Payment} = \text{Monthly Payment} \times \text{Duration} \][/tex]
Substituting the values:
[tex]\[ \text{Total Payment} = 183.00 \times 36 \][/tex]
The total payment over 36 months is \[tex]$6588.00. 5. Calculate the total interest paid: This is done by subtracting the principal amount from the total payment amount. \[ \text{Interest Paid} = \text{Total Payment} - \text{Principal} \] Substituting the values: \[ \text{Interest Paid} = 6588.00 - 5800.00 \] The total interest paid over the life of the loan is \$[/tex]788.00.

Therefore, the borrower will pay \$788.00 in interest over the life of Loan 2.