Type the correct answer in each box. Use numerals instead of words.

A company manufactures 2,000 units of its flagship product in a day. The quality control department takes a random sample of 40 units to test for quality. The product is put through a wear-and-tear test to determine the number of days it can last. If the product has a lifespan of less than 26 days, it is considered defective. The table gives the sample data that a quality control manager collected.

\begin{tabular}{|l|l|l|l|l|}
\hline 39 & 31 & 38 & 40 & 29 \\
\hline 32 & 33 & 39 & 35 & 32 \\
\hline 32 & 27 & 30 & 31 & 27 \\
\hline 30 & 29 & 34 & 36 & 25 \\
\hline 30 & 32 & 38 & 35 & 40 \\
\hline 29 & 32 & 31 & 26 & 26 \\
\hline 32 & 26 & 30 & 40 & 32 \\
\hline 39 & 37 & 25 & 29 & 34 \\
\hline
\end{tabular}

The point estimate of the population mean is [tex]$\square$[/tex], and the point estimate of the proportion of defective units is [tex]$\square$[/tex].



Answer :

To calculate the point estimate of the population mean, we need to determine the average lifespan of the sample data provided. The sample data consists of the following 40 values:

[tex]\[ 39, 31, 38, 40, 29, 32, 33, 39, 35, 32, 32, 27, 30, 31, 27, 30, 29, 34, 36, 25, 30, 32, 38, 35, 40, 29, 32, 31, 26, 26, 32, 26, 30, 40, 32, 39, 37, 25, 29, 34 \][/tex]

We calculate the mean (average) of these values to obtain the point estimate of the population mean.

The point estimate of the population mean is 32.3.

To find the point estimate of the proportion of defective units, we need to count how many of the units in the sample have a lifespan of less than 26 days.

From the sample data provided, the units with a lifespan less than 26 days are:

[tex]\[ 25, 25 \][/tex]

There are 2 defective units out of the 40 sampled units.

The proportion of defective units is:
[tex]\[ \frac{\text{Number of defective units}}{\text{Total number of units}} = \frac{2}{40} = 0.05 \][/tex]

Therefore, the point estimate of the proportion of defective units is 0.05.