Find the hypotenuse of each isosceles right triangle when the legs are of the given measure.

Given: [tex]\(8\)[/tex]

The length of the hypotenuse of an isosceles right triangle can be calculated using the formula [tex]\( \text{Hypotenuse} = \sqrt{2} \times \text{leg} \)[/tex].

Given [tex]\( \text{leg} = 8 \)[/tex], the hypotenuse is [tex]\( 8\sqrt{2} \)[/tex].

(Note: The tabular content provided appears to be unrelated and has been excluded from the problem.)



Answer :

To find the hypotenuse of an isosceles right triangle when the legs are each of length 8, we can follow these steps:

1. Recall the properties of an isosceles right triangle: In such triangles, the two legs are of equal length, and the angles opposite these legs are each 45 degrees. The triangle is a special case of a right triangle.

2. Use the Pythagorean Theorem: According to this theorem, in any right triangle with legs [tex]\(a\)[/tex] and [tex]\(b\)[/tex] and hypotenuse [tex]\(c\)[/tex], the relationship between these sides is given by:
[tex]\[ a^2 + b^2 = c^2 \][/tex]

3. Substitute the leg lengths into the formula: Since both legs are equal in length and each leg is 8 units:
[tex]\[ 8^2 + 8^2 = c^2 \][/tex]

4. Simplify the equation:
[tex]\[ 64 + 64 = c^2 \][/tex]
[tex]\[ 128 = c^2 \][/tex]

5. Solve for the hypotenuse [tex]\(c\)[/tex]:
[tex]\[ c = \sqrt{128} \][/tex]

6. Simplify the square root:
[tex]\[ \sqrt{128} = \sqrt{64 \times 2} = \sqrt{64} \times \sqrt{2} = 8\sqrt{2} \][/tex]

7. Calculate the numerical value of [tex]\(8\sqrt{2}\)[/tex]:
[tex]\[ 8\sqrt{2} \approx 8 \times 1.414213562 = 11.313708498984761 \][/tex]

So, the hypotenuse of the isosceles right triangle with legs of length 8 is approximately [tex]\(11.313708498984761\)[/tex].