If [tex]\( s(x) = x - 7 \)[/tex] and [tex]\( t(x) = 4x^2 - x + 3 \)[/tex], which expression is equivalent to [tex]\( (t \circ s)(x) \)[/tex]?

[tex]\[
\begin{array}{c}
A. \ 4(x-7)^2 - (x-7) + 3 \\
B. \ 4x^2 - x + 3 - 7 \\
C. \ 4(x-7)^2 - x - 7 + 3 \\
D. \ (4x^2 - x + 3)(x - 7)
\end{array}
\][/tex]



Answer :

To determine which expression is equivalent to [tex]\((t \circ s)(x)\)[/tex], let's recall that the composition of functions [tex]\((t \circ s)(x)\)[/tex] means [tex]\(t(s(x))\)[/tex]. This process involves substituting [tex]\(s(x)\)[/tex] into the function [tex]\(t(x)\)[/tex].

Given the functions:
[tex]\[ s(x) = x - 7 \][/tex]
[tex]\[ t(x) = 4x^2 - x + 3 \][/tex]

1. Substitute [tex]\(s(x)\)[/tex] into [tex]\(t(x)\)[/tex]:

[tex]\[ t(s(x)) = t(x - 7) \][/tex]

2. We need to substitute [tex]\(x - 7\)[/tex] for every [tex]\(x\)[/tex] in [tex]\(t(x)\)[/tex]:

[tex]\[ t(x-7) = 4(x-7)^2 - (x-7) + 3 \][/tex]

3. Simplify [tex]\(t(x-7)\)[/tex]:

[tex]\[ t(x-7) = 4(x-7)^2 - (x-7) + 3 \][/tex]

Expanding [tex]\( (x-7)^2 \)[/tex]:

[tex]\[ (x-7)^2 = x^2 - 14x + 49 \][/tex]

Now substitute this back into the expression:

[tex]\[ 4(x-7)^2 = 4(x^2 - 14x + 49) = 4x^2 - 56x + 196 \][/tex]

Thus:

[tex]\[ t(x-7) = 4(x^2 - 14x + 49) - (x - 7) + 3 \][/tex]

[tex]\[ = 4x^2 - 56x + 196 - x + 7 + 3 \][/tex]

Combine like terms:

[tex]\[ = 4x^2 - 57x + 206 \][/tex]

That final expression matches with:
[tex]\[ -x + 4(x - 7)^2 + 10 \][/tex]
which simplifies back to:
[tex]\[ 4(x-7)^2 - (x-7) + 3 \][/tex]

Thus, the expression that is equivalent to [tex]\((t \circ s)(x)\)[/tex] is:

[tex]\[ \boxed{4(x-7)^2 - (x-7) + 3} \][/tex]