To determine the type of reaction represented by the equation [tex]\( AB + CD \rightarrow AD + CB \)[/tex], let's analyze the reactants and the products:
1. Identify the Reactants and Products:
- Reactants: [tex]\( AB \)[/tex] and [tex]\( CD \)[/tex]
- Products: [tex]\( AD \)[/tex] and [tex]\( CB \)[/tex]
2. Observe the Changes:
- The reactant [tex]\( AB \)[/tex] combines with [tex]\( CD \)[/tex] and exchanges partners to form products [tex]\( AD \)[/tex] and [tex]\( CB \)[/tex].
3. Classify the Reaction:
- In this process, element [tex]\( A \)[/tex] in the compound [tex]\( AB \)[/tex] is displacing element [tex]\( C \)[/tex] in the compound [tex]\( CD \)[/tex] to form [tex]\( AD \)[/tex], while element [tex]\( C \)[/tex] combines with element [tex]\( B \)[/tex] to form [tex]\( CB \)[/tex].
This exchange of partners between two reacting compounds to form two new compounds characterizes a double displacement reaction.
Therefore, the reaction [tex]\( AB + CD \rightarrow AD + CB \)[/tex] is a double displacement reaction.
