A random number generator assigned each pepper to one of two groups. The weights of the peppers in each group, given three randomizations, appear in the tables below.

\begin{tabular}{|c|c|}
\hline \multicolumn{2}{|c|}{First Randomization} \\
\hline Group A & Group B \\
\hline 13.6 & 9.2 \\
\hline 12.1 & 8.2 \\
\hline 15.9 & 11.5 \\
\hline 11.2 & 13.8 \\
\hline 9.7 & 14.6 \\
\hline
\end{tabular}

\begin{tabular}{|c|c|}
\hline Second Randomization \\
\hline Group A & Group B \\
\hline 8.2 & 12.1 \\
\hline 13.8 & 14.6 \\
\hline 15.9 & 13.6 \\
\hline 9.2 & 11.2 \\
\hline 9.7 & 11.5 \\
\hline
\end{tabular}

\begin{tabular}{|c|c|}
\hline \multicolumn{2}{|c|}{Third Randomization} \\
\hline Group A & Group B \\
\hline 8.2 & 12.1 \\
\hline 9.7 & 13.8 \\
\hline 11.5 & 13.6 \\
\hline 14.6 & 11.2 \\
\hline 15.9 & 9.2 \\
\hline
\end{tabular}

For each table, calculate the mean weight for each group, [tex]\bar{x}_A[/tex] and [tex]\bar{x}_B[/tex], and find the difference between the mean of group A and the mean of group B ([tex]\left(\bar{x}_A-\bar{x}_B\right)[/tex]).

Type the correct answer in each box.

1. After the first randomization, [tex]\bar{x}_A[/tex] is [tex]\square[/tex], [tex]\bar{x}_B[/tex] is [tex]\square[/tex], and [tex]\left(\bar{x}_A-\bar{x}_B\right)[/tex] is [tex]\square[/tex].

2. After the second randomization, [tex]\bar{x}_A[/tex] is [tex]\square[/tex], [tex]\bar{x}_B[/tex] is [tex]\square[/tex], and [tex]\left(\bar{x}_A-\bar{x}_B\right)[/tex] is [tex]\square[/tex].

3. After the third randomization, [tex]\bar{x}_A[/tex] is [tex]\square[/tex], [tex]\bar{x}_B[/tex] is [tex]\square[/tex], and [tex]\left(\bar{x}_A-\bar{x}_B\right)[/tex] is [tex]\square[/tex].