The boiling points of diatomic halogens are compared in the table below:

\begin{tabular}{|c|c|}
\hline Molecule & Boiling Point \\
\hline [tex]$F_2$[/tex] & [tex]$-188^{\circ}C$[/tex] \\
\hline [tex]$Cl_2$[/tex] & [tex]$-34^{\circ}C$[/tex] \\
\hline [tex]$Br_2$[/tex] & [tex]$59^{\circ}C$[/tex] \\
\hline [tex]$I_2$[/tex] & [tex]$184^{\circ}C$[/tex] \\
\hline
\end{tabular}

Diatomic bromine has weaker intermolecular forces than diatomic fluorine.

A. True
B. False



Answer :

To determine whether diatomic bromine (Br_2) has weaker intermolecular forces than diatomic fluorine (F_2), we need to understand how boiling points are related to intermolecular forces.

Boiling Points and Intermolecular Forces:
- The boiling point of a substance is the temperature at which it changes from a liquid to a gas.
- Higher boiling points indicate stronger intermolecular forces because more energy (in the form of heat) is required to separate the molecules and turn the substance into gas.
- Conversely, lower boiling points indicate weaker intermolecular forces since less energy is needed for the phase change.

Comparison of Boiling Points:
- [tex]\(F_2\)[/tex] (Fluorine): [tex]\(-188^{\circ}C\)[/tex]
- [tex]\(Br_2\)[/tex] (Bromine): [tex]\(59^{\circ}C\)[/tex]

By examining the data:
1. The boiling point of [tex]\(F_2\)[/tex] is [tex]\(-188^{\circ}C\)[/tex], which is much lower than the boiling point of [tex]\(Br_2\)[/tex], which is [tex]\(59^{\circ}C\)[/tex].
2. Since [tex]\(F_2\)[/tex] has a lower boiling point, it implies that it has weaker intermolecular forces compared to [tex]\(Br_2\)[/tex].

Given this reasoning, it is clear that diatomic bromine ([tex]\(Br_2\)[/tex]) does not have weaker intermolecular forces than diatomic fluorine ([tex]\(F_2\)[/tex]). Therefore, the answer is:

False.