Corey gets paid [tex]$\$[/tex]6[tex]$ per hour to work at a snack stand. This weekend, he worked on both Saturday and Sunday. He made a total of \$[/tex]48. Corey worked for 3 hours on Saturday. For how many hours did he work on Sunday?

Let [tex]$x$[/tex] = hours spent working on Sunday. Choose the equation and solution steps that correctly represent this problem.

A.
[tex]$
\begin{array}{c}
3(x+6)=48 \\
3(x+6-6)=48-6 \\
3x=42 \\
\frac{3x}{3}=\frac{42}{3} \\
x=14
\end{array}
$[/tex]
Corey worked for 14 hours on Sunday.

B.
[tex]$
\begin{array}{c}
6(x+3)=48 \\
6(x+3-3)=48-3 \\
6x=45 \\
\frac{6x}{6}=\frac{45}{6} \\
x=\frac{15}{2} \\
x=7 \frac{1}{2}
\end{array}
$[/tex]
Corey worked for [tex]$7 \frac{1}{2}$[/tex] hours on Sunday.

C.
[tex]$
\begin{array}{c}
3(x+6)=48 \\
\frac{3(x+6)}{3}=\frac{48}{3} \\
(x+6)=16 \\
x+6-6=16-6 \\
x=10
\end{array}
$[/tex]
Corey worked for 10 hours on Sunday.

D.
[tex]$6(x+3)=48$[/tex]
[tex]$
\begin{array}{c}
\frac{6(x+3)}{6}=\frac{48}{6} \\
(x+3)=8 \\
x+3-3=8-3 \\
x=5
\end{array}
$[/tex]
Corey worked for 5 hours on Sunday.



Answer :

Let's carefully break down the given problem and solve it step-by-step to determine how many hours Corey worked on Sunday.

1. Corey gets paid \[tex]$6 per hour. 2. He worked 3 hours on Saturday. 3. Corey made a total of \$[/tex]48 over the weekend.
4. Let [tex]\( x \)[/tex] be the number of hours Corey worked on Sunday.

First, we calculate the pay Corey earned on Saturday:
[tex]\[ \text{Pay on Saturday} = \text{hours worked on Saturday} \times \text{rate per hour} = 3 \times 6 = 18 \text{ dollars} \][/tex]

Next, we determine how much he earned on Sunday by subtracting his Saturday earnings from his total earnings:
[tex]\[ \text{Pay on Sunday} = \text{total earnings} - \text{Pay on Saturday} = 48 - 18 = 30 \text{ dollars} \][/tex]

Since Corey is paid \$6 per hour, we can find the number of hours he worked on Sunday by dividing the earnings on Sunday by his rate:
[tex]\[ x = \frac{\text{Pay on Sunday}}{\text{rate per hour}} = \frac{30}{6} = 5 \text{ hours} \][/tex]

Thus, Corey worked for 5 hours on Sunday. The correct equation and solution steps match option D:
[tex]\[ 6(x+3)=48 \][/tex]
[tex]\[ \begin{array}{c} \frac{6(x+3)}{6}=\frac{48}{6} \\ (x+3)=8 \\ x+3-3=8-3 \\ x=5 \end{array} \][/tex]

So, Corey worked for [tex]\(5\)[/tex] hours on Sunday.