A restaurant hands out a scratch-off game ticket with prizes worth various dollar amounts. The back of the ticket lists the probabilities of winning each dollar value:

- 0.1 for [tex]$\$[/tex] 5[tex]$
- 0.05 for $[/tex]\[tex]$ 10$[/tex]
- 0.004 for [tex]$\$[/tex] 75[tex]$
- 0.003 for $[/tex]\[tex]$ 100$[/tex]

What is the probability that the ticket is worth at least [tex]$\$[/tex] 75[tex]$?

$[/tex]\square$



Answer :

To find the probability that the ticket is worth at least [tex]$75, we need to consider the probabilities of winning both $[/tex]75 and [tex]$100 prizes. Hence, we will sum these probabilities. 1. Probability of winning $[/tex]75: According to the given information, the probability of winning a [tex]$75 prize is 0.004. 2. Probability of winning $[/tex]100: According to the given information, the probability of winning a [tex]$100 prize is 0.003. 3. Probability of ticket being worth at least $[/tex]75:
To find this, we add the probabilities of winning the [tex]$75 and $[/tex]100 prizes.

[tex]\[ \text{Probability of at least $75 prize} = \text{Probability of $75 prize} + \text{Probability of $100 prize} \][/tex]
[tex]\[ \text{Probability of at least $75 prize} = 0.004 + 0.003 \][/tex]

When we sum these probabilities, we get:
[tex]\[ \text{Probability of at least $75 prize} = 0.004 + 0.003 = 0.007 \][/tex]

Therefore, the probability that the ticket is worth at least $75 is [tex]\(0.007\)[/tex].