Answered

What is the force used when a 7 kg bowling ball is rolled with an acceleration of 3 m/s²?

Use the formula below to find the force in Newtons ([tex]\(N\)[/tex]):

[tex]\[
\begin{array}{l}
F = ma \\
F = 7 \, \text{kg} \times 3 \, \text{m/s}^2 \\
F =
\end{array}
\][/tex]



Answer :

To find the force exerted on a 7 kg bowling ball accelerating at 3 m/s², we use Newton's Second Law of Motion, which states that the force applied to an object is equal to the mass of the object times its acceleration. The formula is given by:

[tex]\[ F = ma \][/tex]

Here:
- [tex]\( m \)[/tex] is the mass of the object.
- [tex]\( a \)[/tex] is the acceleration of the object.
- [tex]\( F \)[/tex] is the force applied.

Given:
- The mass ([tex]\( m \)[/tex]) of the bowling ball is 7 kg.
- The acceleration ([tex]\( a \)[/tex]) is 3 m/s².

Now, substitute the given values into the formula:

[tex]\[ F = 7 \, \text{kg} \times 3 \, \text{m/s}² \][/tex]

Next, multiply the values:

[tex]\[ F = 21 \, \text{N} \][/tex]

Hence, the force exerted on the 7 kg bowling ball is 21 Newtons.