At a car dealership, the purchases for one month are recorded in the table below:

\begin{tabular}{|l|c|c|c|}
\hline
& Sedan & SUV & Truck \\
\hline
Red & 17 & 7 & 3 \\
\hline
Blue & 17 & 19 & 23 \\
\hline
White & 43 & 37 & 53 \\
\hline
\end{tabular}

If we choose a customer at random, what is the probability that they have purchased an SUV or it is blue?

[tex]\[ P(\text{Blue or SUV}) = \][/tex]

Give your answer in simplest form.



Answer :

To determine the probability that a customer has purchased an SUV or a blue car, let's go through the calculations step-by-step:

1. Calculate the total number of cars sold:
We sum up all the cars regardless of color or type.

[tex]\[ \text{Total number of cars} = 17 + 17 + 43 + 7 + 19 + 37 + 3 + 23 + 53 = 219 \][/tex]

2. Calculate the total number of blue cars:
We add up the number of blue cars for each type.

[tex]\[ \text{Total number of blue cars} = 17\ (\text{Sedan}) + 19\ (\text{SUV}) + 23\ (\text{Truck}) = 59 \][/tex]

3. Calculate the total number of SUVs:
We add up all the cars that are SUVs, regardless of color.

[tex]\[ \text{Total number of SUVs} = 7\ (\text{Red}) + 19\ (\text{Blue}) + 37\ (\text{White}) = 63 \][/tex]

4. Calculate the number of blue SUVs:
Specifically identify the blue SUVs.

[tex]\[ \text{Number of blue SUVs} = 19 \][/tex]

5. Calculate the probability of a customer having purchased an SUV or a blue car:
We use the formula for the probability of the union of two events:

[tex]\[ P(\text{Blue or SUV}) = P(\text{Blue}) + P(\text{SUV}) - P(\text{Blue and SUV}) \][/tex]

Substituting the numbers, we get:

[tex]\[ P(\text{Blue or SUV}) = \frac{59}{219} + \frac{63}{219} - \frac{19}{219} \][/tex]

Combining the fractions:

[tex]\[ P(\text{Blue or SUV}) = \frac{59 + 63 - 19}{219} = \frac{103}{219} \][/tex]

This fraction simplifies to:

[tex]\[ P(\text{Blue or SUV}) \approx 0.4703196347031963 \][/tex]

Thus, the probability that a randomly chosen customer purchased an SUV or a blue car is approximately [tex]\(0.4703\)[/tex].