Events [tex]$A$[/tex] and [tex]$B$[/tex] are independent. The probability of event [tex][tex]$A$[/tex][/tex] occurring is 0.64. The probability of events [tex]$A$[/tex] and [tex]$B$[/tex] occurring together is 0.24.

What is the probability of event [tex][tex]$B$[/tex][/tex]?

Enter a decimal, to the nearest thousandth, in the box.

[tex]P(B) =[/tex] [tex]\square[/tex]



Answer :

To find the probability of event [tex]\( B \)[/tex] given that events [tex]\( A \)[/tex] and [tex]\( B \)[/tex] are independent, we can use the definition of independent events. For two independent events [tex]\( A \)[/tex] and [tex]\( B \)[/tex]:

[tex]\[ P(A \text{ and } B) = P(A) \times P(B) \][/tex]

We are given two pieces of information:
1. The probability of event [tex]\( A \)[/tex] occurring, [tex]\( P(A) = 0.64 \)[/tex]
2. The probability of both events [tex]\( A \)[/tex] and [tex]\( B \)[/tex] occurring together, [tex]\( P(A \text{ and } B) = 0.24 \)[/tex]

We can rearrange the formula to solve for [tex]\( P(B) \)[/tex]:

[tex]\[ P(B) = \frac{P(A \text{ and } B)}{P(A)} \][/tex]

Substitute the given values into the equation:

[tex]\[ P(B) = \frac{0.24}{0.64} \][/tex]

Perform the division:

[tex]\[ P(B) = 0.375 \][/tex]

Therefore, the probability of event [tex]\( B \)[/tex] is:

[tex]\[ P(B) = 0.375 \][/tex]

Hence, to the nearest thousandth, the probability of event [tex]\( B \)[/tex] is [tex]\( 0.375 \)[/tex].