Answered

A quantity with an initial value of 160 grows continuously at a rate of [tex]$0.65\%$[/tex] per hour. What is the value of the quantity after 402 minutes, to the nearest hundredth?



Answer :

Certainly! Let's solve this step-by-step:

1. Understanding the Variables:
- The initial value of the quantity is [tex]\( 160 \)[/tex].
- The continuous growth rate is [tex]\( 0.65\% \)[/tex] per hour.
- The time period given is 402 minutes.

2. Convert Minutes to Hours:
To use the growth rate effectively, we need to convert the time from minutes to hours.
[tex]\[ \text{Time in hours} = \frac{402}{60} = 6.7 \text{ hours} \][/tex]

3. Continuous Growth Formula:
The formula to calculate the value of a quantity after a certain period of continuous growth is:
[tex]\[ A = P \times e^{rt} \][/tex]
where:
[tex]\[ A \text{ is the final amount} \][/tex]
[tex]\[ P \text{ is the initial amount} \][/tex]
[tex]\[ r \text{ is the growth rate} \][/tex]
[tex]\[ t \text{ is the time period} \][/tex]

4. Substitute the Values into the Formula:
Here, [tex]\( P = 160 \)[/tex], [tex]\( r = 0.0065 \)[/tex] (since [tex]\( 0.65\% = 0.0065 \)[/tex] in decimal form), and [tex]\( t = 6.7 \)[/tex] hours.

To calculate the value after 6.7 hours:
[tex]\[ A = 160 \times e^{0.0065 \times 6.7} \][/tex]

5. Evaluate the Expression:
Using [tex]\( e \)[/tex] as the base of the natural logarithm, we evaluate the exponent:
[tex]\[ e^{0.0065 \times 6.7} \approx 1.044512218 \][/tex]
Then multiply this result by the initial amount:
[tex]\[ A = 160 \times 1.044512218 \approx 167.12195497877417 \][/tex]

6. Round the Final Value:
To find the final value to the nearest hundredth:
[tex]\[ A \approx 167.12 \][/tex]

Hence, after 402 minutes, the value of the quantity, rounded to the nearest hundredth, is [tex]\( 167.12 \)[/tex].