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Here is the reformatted question or task:

Simplify the following expression:

[tex]\[ \frac{9x + 3}{25} \][/tex]



Answer :

To solve the equation [tex]\(\frac{9x + 3}{25} = 0\)[/tex], follow these steps:

1. Understand the Equation:
We have [tex]\(\frac{9x + 3}{25} = 0\)[/tex].

2. Eliminate the Denominator:
Multiply both sides of the equation by 25 to get rid of the denominator:
[tex]\[ 25 \cdot \frac{9x + 3}{25} = 25 \cdot 0 \][/tex]
This simplifies to:
[tex]\[ 9x + 3 = 0 \][/tex]

3. Isolate the Variable:
Subtract 3 from both sides to isolate the term containing [tex]\(x\)[/tex]:
[tex]\[ 9x = -3 \][/tex]

4. Solve for [tex]\(x\)[/tex]:
Divide both sides by 9 to solve for [tex]\(x\)[/tex]:
[tex]\[ x = \frac{-3}{9} \][/tex]
Simplify the fraction:
[tex]\[ x = -\frac{1}{3} \][/tex]

Thus, the solution to the equation [tex]\(\frac{9x + 3}{25} = 0\)[/tex] is:
[tex]\[ x = -\frac{1}{3} \][/tex]