First, we need to determine the total capacity of the pot. The pot has a capacity of [tex]\( 5 \frac{1}{2} \)[/tex] quarts. Converting this to an improper fraction or a decimal, we find that:
[tex]\[ 5 \frac{1}{2} = 5 + \frac{1}{2} = 5.5 \text{ quarts} \][/tex]
Next, we need to calculate how much water is initially in the pot. The problem states the pot is filled to [tex]\( \frac{2}{3} \)[/tex] of its capacity. Thus, the amount of water in the pot is:
[tex]\[ 5.5 \times \frac{2}{3} \approx 3.6667 \text{ quarts} \][/tex]
To find out how many more quarts of water the pot can hold, we subtract the amount of water currently in the pot from its total capacity:
[tex]\[ 5.5 - 3.6667 \approx 1.8333 \text{ quarts} \][/tex]
In conclusion, the pot can hold approximately [tex]\( 1.8333 \)[/tex] more quarts of water.
