Answer :

GinnyAnswer
Sure, let's break down the division problems step by step.

### Problem 1: [tex]\( 60 \div 6 \)[/tex]

1. Setup the division: We have [tex]\( 6 \)[/tex] as the divisor and [tex]\( 60 \)[/tex] as the dividend.
```
6 ) 60
```

2. Determine how many times 6 goes into 60:
- 6 goes into 60 exactly 10 times.

3. Write the result of 10 above the dividend:
```
10
6 ) 60
```

4. Multiply and subtract:
- Multiply 6 by 10 to get 60.
- Subtract 60 from 60 to get 0.

This gives us the result of the division:

[tex]\( 60 \div 6 = 10 \)[/tex]

### Problem 2: [tex]\( 81 \div 9 \)[/tex]

1. Setup the division: We have [tex]\( 9 \)[/tex] as the divisor and [tex]\( 81 \)[/tex] as the dividend.
```
9 ) 81
```

2. Determine how many times 9 goes into 81:
- 9 goes into 81 exactly 9 times.

3. Write the result of 9 above the dividend:
```
9
9 ) 81
```

4. Multiply and subtract:
- Multiply 9 by 9 to get 81.
- Subtract 81 from 81 to get 0.

This gives us the result of the division:

[tex]\( 81 \div 9 = 9 \)[/tex]

So, the answers to the division problems are:

1. [tex]\( 60 \div 6 = 10 \)[/tex]
2. [tex]\( 81 \div 9 = 9 \)[/tex]

These are the final results: [tex]\( 10.0 \)[/tex] and [tex]\( 9.0 \)[/tex].

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