55. If one of the roots of the quadratic equation [tex]$x^2 + px - 4 = 0$[/tex] is -4, what is the value of [tex]p[/tex]?



Answer :

To find the value of [tex]\( p \)[/tex] in the quadratic equation [tex]\( x^2 + px - 4 = 0 \)[/tex], given that -4 is one of the roots, we can use the fact that if [tex]\(-4\)[/tex] is a root, then it must satisfy the equation. Here’s a step-by-step solution:

1. The quadratic equation is given by [tex]\( x^2 + px - 4 = 0 \)[/tex].
2. Substitute [tex]\( x = -4 \)[/tex] into the equation because [tex]\(-4\)[/tex] is a root:
[tex]\[ (-4)^2 + p(-4) - 4 = 0 \][/tex]

3. Simplify the equation:
[tex]\[ 16 - 4p - 4 = 0 \][/tex]

4. Combine like terms:
[tex]\[ 12 - 4p = 0 \][/tex]

5. Solve for [tex]\( p \)[/tex]:
[tex]\[ 12 = 4p \][/tex]

6. Divide both sides by 4:
[tex]\[ p = 3 \][/tex]

Thus, the value of [tex]\( p \)[/tex] is 3.