What is [tex]$y=-\frac{1}{3}x-9$[/tex] written in standard form?

Choose 1 answer:

A. [tex]\frac{1}{3}x + y + 9 = 0[/tex]

B. [tex]y = -\frac{1}{3}(x + 27)[/tex]

C. [tex]3y = -x - 27[/tex]

D. [tex]x + 3y = -27[/tex]



Answer :

To convert the given equation [tex]\( y = -\frac{1}{3}x - 9 \)[/tex] into standard form [tex]\( Ax + By + C = 0 \)[/tex], follow these steps:

1. Multiply both sides by 3: This step is to eliminate the fraction. Multiplying each term by 3 gives:
[tex]\[ 3y = -x - 27 \][/tex]

2. Rearrange the terms to fit standard form: In standard form, the equation should be in the format [tex]\( Ax + By + C = 0 \)[/tex]. This requires moving all terms to one side of the equation. Add [tex]\( x \)[/tex] to both sides:
[tex]\[ x + 3y = -27 \][/tex]

Thus, the equation in standard form is:
[tex]\[ x + 3y = -27 \][/tex]

Therefore, the correct answer is:
(D) [tex]\(\boxed{x + 3y = -27}\)[/tex]