The function [tex]$N(t) = \frac{30,000}{1 + 40e^{-2.0t}}$[/tex] describes the number of people, [tex]$N(t)$[/tex], who become ill with a virus [tex][tex]$t$[/tex][/tex] weeks after its initial outbreak in a town with 30,000 inhabitants. The horizontal asymptote in the graph indicates that there is a limit to the epidemic's growth. Complete parts (a) through (c) below.

a. How many people became ill with the virus when the epidemic began?

When the epidemic began, [tex]$t = 0$[/tex].

When the epidemic began, approximately [tex] \square [/tex] people were ill with the virus.

(Round to the nearest person as needed.)



Answer :

To determine how many people became ill with the virus when the epidemic began, we need to evaluate the given function [tex]\( N(t) \)[/tex] at the point [tex]\( t = 0 \)[/tex].

Given the function:
[tex]\[ N(t) = \frac{30,000}{1 + 40e^{-2.0t}} \][/tex]

we substitute [tex]\( t = 0 \)[/tex] into the function:

[tex]\[ N(0) = \frac{30,000}{1 + 40e^{-2.0 \cdot 0}} \][/tex]

Since [tex]\( e^0 = 1 \)[/tex], we get:

[tex]\[ N(0) = \frac{30,000}{1 + 40 \cdot 1} \][/tex]

Simplify the denominator:

[tex]\[ N(0) = \frac{30,000}{1 + 40} = \frac{30,000}{41} \][/tex]

By evaluating this expression, we find the initial number of people who were ill with the virus:

[tex]\[ N(0) \approx 732 \][/tex]

Thus, when the epidemic began, approximately 732 people were ill with the virus.