Certainly! Let's fill in the table step-by-step by determining the required values for both the isotope of Gallium (Ga) with the symbol [tex]\(\text{ }^{69} Ga ^{3+} \)[/tex] and an unknown element with a net charge of [tex]\( 2- \)[/tex]:
1. For the isotope [tex]\(\text{ }^{69} Ga ^{3+} \)[/tex]:
- Number of protons: The atomic number of Gallium (Ga) is 31, so it has 31 protons.
- Number of neutrons: The mass number is 69. Neutrons can be found by subtracting the number of protons from the mass number: [tex]\( 69 - 31 = 38 \)[/tex] neutrons.
- Number of electrons: Since this is a [tex]\(3+\)[/tex] charged ion, it has lost 3 electrons compared to the neutral atom. A neutral Gallium atom would have 31 electrons, so [tex]\( 31 - 3 = 28 \)[/tex] electrons.
- Atomic number: Is the same as the number of protons, which is 31.
- Mass number: Already given directly as 69.
- Net charge: Given as [tex]\( 3+ \)[/tex].
2. For the unknown element with [tex]\(2-\)[/tex] charge:
- Number of protons: Given as 34 protons.
- Number of neutrons: Given as 46 neutrons.
- Number of electrons: Since this is a [tex]\(2-\)[/tex] charged ion, it has gained 2 electrons compared to the neutral atom. A neutral atom would have 34 electrons, so [tex]\( 34 + 2 = 36 \)[/tex] electrons.
- Atomic number: The same as the number of protons, which is 34.
- Mass number: Sum of protons and neutrons: [tex]\( 34 + 46 = 80 \)[/tex].
- Net charge: Given as [tex]\( 2- \)[/tex].
Now, let's fill in the table with these values:
\begin{tabular}{|l|l|l|}
\hline
Symbol & [tex]\(\text{ }^{69} Ga ^{3+} \)[/tex] & \\
\hline
Number of protons & 31 & 34 \\
\hline
Number of neutrons & 38 & 46 \\
\hline
Number of electrons & 28 & 36 \\
\hline
Atomic number & 31 & 34 \\
\hline
Mass number & 69 & 80 \\
\hline
Net charge & [tex]\(3+\)[/tex] & [tex]\(2-\)[/tex] \\
\hline
\end{tabular}
This completes the table with all required values.
