Answered

1. A man hits a golf ball [tex]\((0.2 \, \text{kg})\)[/tex], which accelerates at a rate of [tex]\(20 \, \text{m/s}^2\)[/tex]. What amount of force acted on the ball?



Answer :

To determine the amount of force acted on the golf ball, we can use Newton's second law of motion. Newton's second law of motion states that the force acting on an object is equal to the mass of the object multiplied by its acceleration. Mathematically, this is expressed as:

[tex]\[ F = m \times a \][/tex]

Where:
- [tex]\( F \)[/tex] is the force
- [tex]\( m \)[/tex] is the mass of the object
- [tex]\( a \)[/tex] is the acceleration of the object

Given the problem:

1. The mass of the golf ball [tex]\( m \)[/tex] is [tex]\( 0.2 \, \text{kg} \)[/tex].
2. The acceleration [tex]\( a \)[/tex] of the golf ball is [tex]\( 20 \, \text{m/s}^2 \)[/tex].

Now, substituting the given values into the formula:

[tex]\[ F = 0.2 \, \text{kg} \times 20 \, \text{m/s}^2 \][/tex]

[tex]\[ F = 4.0 \, \text{N} \][/tex]

Therefore, the amount of force that acted on the golf ball is [tex]\( 4.0 \, \text{N} \)[/tex].