Harlene tosses two number cubes. If a sum of 8 or 12 comes up, she gets 9 points. If not, she loses 2 points. What is the expected value of the number of points for one roll?

A. [tex]-\frac{2}{3}[/tex]
B. [tex]-\frac{1}{6}[/tex]
C. [tex]\frac{1}{6}[/tex]
D. [tex]\frac{2}{3}[/tex]



Answer :

To find the expected value of the number of points Harlene gets for one roll of two number cubes, we need to follow a series of steps:

1. Determine the possible outcomes and their respective probabilities:

There are a total of [tex]\(36\)[/tex] possible outcomes when rolling two number cubes (each cube has [tex]\(6\)[/tex] faces, thus [tex]\(6 \times 6 = 36\)[/tex] outcomes).

Let's identify the probabilities of getting a sum of [tex]\(8\)[/tex] or [tex]\(12\)[/tex]:

- Sum of [tex]\(8\)[/tex]: There are [tex]\(5\)[/tex] combinations that produce this sum [tex]\((2, 6), (3, 5), (4, 4), (5, 3), (6, 2)\)[/tex].
- Sum of [tex]\(12\)[/tex]: There is [tex]\(1\)[/tex] combination that produces this sum [tex]\((6, 6)\)[/tex].

The total number of combinations that result in a sum of [tex]\(8\)[/tex] or [tex]\(12\)[/tex] is:
[tex]\(5 + 1 = 6\)[/tex].

Therefore, the probability of rolling a sum of [tex]\(8\)[/tex] or [tex]\(12\)[/tex] is:
[tex]\[ \frac{6}{36} = \frac{1}{6} \][/tex]

The probability of not rolling a sum of [tex]\(8\)[/tex] or [tex]\(12\)[/tex] is:
[tex]\[ 1 - \frac{1}{6} = \frac{5}{6} \][/tex]

2. Determine the points associated with each outcome:

- If a sum of [tex]\(8\)[/tex] or [tex]\(12\)[/tex] comes up, Harlene gets [tex]\(9\)[/tex] points.
- If the sum is anything else, Harlene loses [tex]\(2\)[/tex] points.

3. Calculate the expected value:

The expected value [tex]\(E\)[/tex] is calculated by multiplying each outcome's points by its probability and then summing these products:
[tex]\[ E = \left(\frac{1}{6} \times 9\right) + \left(\frac{5}{6} \times (-2)\right) \][/tex]

Breaking it down:
- The expected contribution from rolling a sum of [tex]\(8\)[/tex] or [tex]\(12\)[/tex] is:
[tex]\[ \frac{1}{6} \times 9 = 1.5 \][/tex]
- The expected contribution from not rolling a sum of [tex]\(8\)[/tex] or [tex]\(12\)[/tex] is:
[tex]\[ \frac{5}{6} \times (-2) = -1.6666666666666667 \][/tex]

Summing these contributions yields the overall expected value:
[tex]\[ E = 1.5 + (-1.6666666666666667) = -0.16666666666666674 \][/tex]

Thus, the expected value of the number of points Harlene gets in one roll is:
[tex]\[ -\frac{1}{6} \][/tex]

So the correct answer is:
[tex]\[ \boxed{-\frac{1}{6}} \][/tex]