What is an equation of the line that is perpendicular to [tex]y - 3 = -4(x + 2)[/tex] and passes through the point [tex](-5, 7)[/tex]?

A. [tex]y - 7 = -4(x + 5)[/tex]

B. [tex]y + 7 = -\frac{1}{4}(x - 5)[/tex]

C. [tex]y + 7 = 4(x - 5)[/tex]

D. [tex]y - 7 = \frac{1}{4}(x + 5)[/tex]



Answer :

Certainly! Let's solve this step-by-step.

1. Identify the given line's slope:

The equation provided is [tex]\(y - 3 = -4(x + 2)\)[/tex]. This is in the point-slope form [tex]\((y - y_1 = m(x - x_1))\)[/tex], where [tex]\(m\)[/tex] is the slope. From this equation, we identify the slope ([tex]\(m\)[/tex]) of the given line as [tex]\(-4\)[/tex].

2. Find the slope of the perpendicular line:

The slope of a line perpendicular to another line is the negative reciprocal of the slope of the given line. Since the slope of the given line is [tex]\(-4\)[/tex], the negative reciprocal of [tex]\(-4\)[/tex] is [tex]\(\frac{1}{4}\)[/tex].

3. Write the equation of the perpendicular line:

We need to find the equation of the line that is perpendicular to the given line and passes through the point [tex]\((-5, 7)\)[/tex].

Using the point-slope form again, [tex]\((y - y_1 = m(x - x_1))\)[/tex], where [tex]\(m\)[/tex] is the slope of the perpendicular line, and [tex]\((x_1, y_1)\)[/tex] is the point [tex]\((-5, 7)\)[/tex]:

[tex]\[ y - 7 = \frac{1}{4}(x + 5) \][/tex]

4. Match the equation to the options provided:

Let's compare the derived equation [tex]\(y - 7 = \frac{1}{4}(x + 5)\)[/tex] with the given options:

A. [tex]\(y - 7 = -4(x + 5)\)[/tex]
B. [tex]\(y + 7 = -\frac{1}{4}(x - 5)\)[/tex]
C. [tex]\(y + 7 = 4(x - 5)\)[/tex]
D. [tex]\(y - 7 = \frac{1}{4}(x + 5)\)[/tex]

The correct option is:
[tex]\[ \text{D. } y - 7 = \frac{1}{4}(x + 5) \][/tex]

To summarize, the equation of the line that is perpendicular to [tex]\(y - 3 = -4(x + 2)\)[/tex] and passes through the point [tex]\((-5, 7)\)[/tex] is [tex]\(y - 7 = \frac{1}{4}(x + 5)\)[/tex].

The correct answer is [tex]\( \text{D. } y - 7 = \frac{1}{4}(x + 5) \)[/tex].