Solve the equation by completing the square. Round to the nearest hundredth if necessary.

[tex]\[ x^2 + 3x = 25 \][/tex]

A. 3.65, -6.65

B. 4.77, 5.22

C. 3.72, -6.72

D. 25.75, -28.75



Answer :

Sure, let's solve the equation [tex]\( x^2 + 3x = 25 \)[/tex] by completing the square, and then we'll determine the answer from the given options.

1. Start with the given equation:
[tex]\[ x^2 + 3x = 25 \][/tex]

2. Move the constant term to the right side of the equation to set it up for completing the square:
[tex]\[ x^2 + 3x - 25 = 0 \][/tex]

3. To complete the square, we need to add and subtract the square of half the coefficient of [tex]\( x \)[/tex]. The coefficient of [tex]\( x \)[/tex] is [tex]\( 3 \)[/tex], so half of it is [tex]\( 1.5 \)[/tex], and its square is [tex]\( (1.5)^2 = 2.25 \)[/tex].

4. Add and subtract [tex]\( 2.25 \)[/tex] to the left side of the equation:
[tex]\[ x^2 + 3x + 2.25 - 2.25 = 25 \][/tex]
[tex]\[ x^2 + 3x + 2.25 = 25 + 2.25 \][/tex]
[tex]\[ x^2 + 3x + 2.25 = 27.25 \][/tex]

5. Now, recognize that the left side is a perfect square trinomial:
[tex]\[ (x + 1.5)^2 = 27.25 \][/tex]

6. Take the square root of both sides of the equation:
[tex]\[ x + 1.5 = \pm \sqrt{27.25} \][/tex]

7. Simplify the square root. We can approximate [tex]\( \sqrt{27.25} \approx 5.22 \)[/tex].

8. Thus, we have two possible equations:
[tex]\[ x + 1.5 = 5.22 \quad \text{or} \quad x + 1.5 = -5.22 \][/tex]

9. Solve for [tex]\( x \)[/tex] in each case:
[tex]\[ x = 5.22 - 1.5 \quad \text{or} \quad x = -5.22 - 1.5 \][/tex]
[tex]\[ x \approx 3.72 \quad \text{or} \quad x \approx -6.72 \][/tex]

10. Therefore, the solutions to the equation [tex]\( x^2 + 3x = 25 \)[/tex] are approximately [tex]\( 3.72 \)[/tex] and [tex]\( -6.72 \)[/tex], rounded to the nearest hundredth.

From the given options, the correct answer is:
[tex]\( 3.72, -6.72 \)[/tex].