What is the inverse of [tex]f(x)=\frac{1}{3} x+2[/tex]?

A. [tex]h(x)=\frac{1}{3} x+2[/tex]
B. [tex]h(x)=\frac{1}{3} x-2[/tex]
C. [tex]h(x)=3 x-2[/tex]
D. [tex]h(x)=3 x-6[/tex]



Answer :

To find the inverse of the function [tex]\( f(x) = \frac{1}{3} x + 2 \)[/tex], we need to follow these steps:

1. Rewrite the function [tex]\( f(x) \)[/tex] as [tex]\( y \)[/tex]:
[tex]\[ y = \frac{1}{3} x + 2 \][/tex]

2. Solve this equation for [tex]\( x \)[/tex]. To do this, we will isolate [tex]\( x \)[/tex] on one side of the equation.

3. Subtract 2 from both sides:
[tex]\[ y - 2 = \frac{1}{3} x \][/tex]

4. Multiply both sides of the equation by 3 to eliminate the fraction:
[tex]\[ 3(y - 2) = x \][/tex]

5. Rewrite the expression by swapping [tex]\( x \)[/tex] and [tex]\( y \)[/tex] to represent the inverse function [tex]\( f^{-1}(x) \)[/tex]:
[tex]\[ f^{-1}(x) = 3(x - 2) \][/tex]

6. Simplify the expression if necessary:
[tex]\[ f^{-1}(x) = 3x - 6 \][/tex]

Thus, the inverse function of [tex]\( f(x) = \frac{1}{3} x + 2 \)[/tex] is [tex]\( f^{-1}(x) = 3x - 6 \)[/tex].

Therefore, the correct answer is:
[tex]\[ h(x) = 3x - 6 \][/tex]