[tex]$f(x) = x^2 + 5x - 1$[/tex] is shifted 3 units left. The result is [tex]$g(x)$[/tex]. What is [tex]$g(x)$[/tex]?

A. [tex]$g(x) = x^2 + 5x + 2$[/tex]

B. [tex]$g(x) = (x + 3)^2 + 5x - 1$[/tex]

C. [tex]$g(x) = (x + 3)^2 + 5(x + 3) - 1$[/tex]

D. [tex]$g(x) = (x - 3)^2 + 5(x - 3) - 1$[/tex]



Answer :

To determine [tex]\( g(x) \)[/tex] when the function [tex]\( f(x) = x^2 + 5x - 1 \)[/tex] is shifted 3 units to the left, we need to understand how horizontal shifts affect the function.

### Step-by-Step Solution:

1. Horizontal Shift by [tex]\( h \)[/tex] Units:
A horizontal shift to the left by [tex]\( h \)[/tex] units involves replacing [tex]\( x \)[/tex] with [tex]\( x + h \)[/tex] in the function. For example, shifting [tex]\( f(x) \)[/tex] 3 units to the left requires us to replace [tex]\( x \)[/tex] with [tex]\( x + 3 \)[/tex].

2. Constructing [tex]\( g(x) \)[/tex]:
To find the new function [tex]\( g(x) \)[/tex] after the horizontal shift:
[tex]\[ g(x) = f(x + 3) \][/tex]

3. Substitution:
Substitute [tex]\( x + 3 \)[/tex] into [tex]\( f(x) \)[/tex]:
[tex]\[ g(x) = f(x + 3) = (x + 3)^2 + 5(x + 3) - 1 \][/tex]

4. Expanding the Expression:
To understand this better, we expand the terms:
[tex]\[ (x + 3)^2 = x^2 + 6x + 9 \][/tex]
[tex]\[ 5(x + 3) = 5x + 15 \][/tex]
So,
[tex]\[ g(x) = x^2 + 6x + 9 + 5x + 15 - 1 \][/tex]

5. Combining the Terms:
Combine all like terms:
[tex]\[ g(x) = x^2 + 6x + 5x + 9 + 15 - 1 = x^2 + 11x + 23 \][/tex]

6. Final Form:
Upon further inspection, the form given by the answer choices does not require final expansion and should be left in the form:
[tex]\[ g(x) = (x + 3)^2 + 5(x + 3) - 1 \][/tex]

### Conclusion:

The correct function for [tex]\( g(x) \)[/tex] after shifting the original function [tex]\( f(x) \)[/tex] 3 units to the left is:
[tex]\[ g(x) = (x+3)^2 + 5(x+3) - 1 \][/tex]

Thus, the right answer is:
[tex]\[ \boxed{C: \; g(x) = (x+3)^2 + 5(x+3) - 1} \][/tex]