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Two students performed the same experiment, testing how far iodine will diffuse through starchy tissue, such as potatoes. They cut 5 potato squares each, all of equal sizes, and placed them into small cups with iodine solution for 15 minutes. Then they measured how far from the edge of the potato the iodine diffused into the potatoes, in millimeters.

[tex]\[
\begin{array}{l|c|c|c|c|c}
& \text{Distance Diffused (mm)} & & & & \\
& \text{Trial 1} & \text{Trial 2} & \text{Trial 3} & \text{Trial 4} & \text{Trial 5} \\
\hline
\text{Student 1} & 3.25 & 3.17 & 3.26 & 3.64 & 3.44 \\
\text{Student 2} & 3.14 & 3.43 & 3.22 & 3.37 & 3.28 \\
\end{array}
\][/tex]

What is the range of Student 1's results?

A. 0.29
B. 3.20
C. 31.35
D. 0.47



Answer :

GinnyAnswer
To find the range of Student 1's results, we'll follow these steps:

1. List the distances diffused for Student 1:
The distances in millimeters (mm) for Student 1 are given as:
[tex]\[ 3.25, 3.17, 3.26, 3.64, 3.44 \][/tex]

2. Identify the maximum and minimum values:
- The maximum value in the list is [tex]\(3.64\)[/tex] mm.
- The minimum value in the list is [tex]\(3.17\)[/tex] mm.

3. Calculate the range:
The range is found by subtracting the minimum value from the maximum value:
[tex]\[ \text{Range} = \text{Maximum} - \text{Minimum} \][/tex]
Substituting the identified values:
[tex]\[ \text{Range} = 3.64 - 3.17 \][/tex]

4. Perform the subtraction:
[tex]\[ 3.64 - 3.17 = 0.47 \text{ mm} \][/tex]

Thus, the range of Student 1's results is [tex]\(0.47\)[/tex] mm. Therefore, the correct answer is:

D. 0.47

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