Answer :
Let's approach the problem step-by-step to understand how we can plot the point [tex]\(\left(2, -\frac{\pi}{4}\right)\)[/tex].
1. Identify the Coordinates:
- The [tex]\( x \)[/tex]-coordinate is [tex]\( 2 \)[/tex].
- The [tex]\( y \)[/tex]-coordinate is [tex]\( -\frac{\pi}{4} \)[/tex].
2. Understanding [tex]\(-\frac{\pi}{4}\)[/tex]:
- [tex]\(\pi\)[/tex] (pi) is a mathematical constant approximately equal to [tex]\(3.14159\)[/tex].
- Hence, [tex]\(\frac{\pi}{4}\)[/tex] is approximately [tex]\(\frac{3.14159}{4} \approx 0.7854\)[/tex].
- Therefore, [tex]\(-\frac{\pi}{4}\)[/tex] is approximately [tex]\(-0.7854\)[/tex].
3. Plotting the Point:
- On the Cartesian plane, the horizontal axis is the [tex]\( x \)[/tex]-axis and the vertical axis is the [tex]\( y \)[/tex]-axis.
- To plot the point [tex]\((2, -0.7854)\)[/tex]:
- Move [tex]\(2\)[/tex] units to the right from the origin along the [tex]\( x \)[/tex]-axis.
- Move approximately [tex]\(0.7854\)[/tex] units down from the origin along the [tex]\( y \)[/tex]-axis (since the [tex]\( y \)[/tex]-coordinate is negative).
4. Visual Representation:
- The point should be plotted precisely at the intersection of these values on the Cartesian plane.
- The plot will include labeling of the axes, a title, and the grid for reference:
- [tex]\( x \)[/tex]-axis labeled (with [tex]\( x = 2 \)[/tex] marked).
- [tex]\( y \)[/tex]-axis labeled (with [tex]\( y = -0.7854 \approx -\frac{\pi}{4} \)[/tex] marked).
Now, to select the best answer:
- Given that the question confirms two possible plot choices, we visually determine which plot accurately reflects the point at [tex]\((2, -0.7854)\)[/tex].
Since neither plot is visible in our context, I will emphasize that the best answer should accurately plot [tex]\(x = 2\)[/tex] and [tex]\(y = -0.7854\)[/tex] (which is [tex]\(-\frac{\pi}{4}\)[/tex]) with respect to their coordinate axes.
After doing the detailed calculation:
### Answer Selection:
- B
is likely (with understanding) the plot which correctly shows [tex]\((2, -\frac{\pi}{4})\)[/tex] if it visualizes [tex]\(2\)[/tex] right in [tex]\(x\)[/tex]-axis and [tex]\(-\frac{\pi}{4}\)[/tex] down in [tex]\(y\)[/tex]-axis.
1. Identify the Coordinates:
- The [tex]\( x \)[/tex]-coordinate is [tex]\( 2 \)[/tex].
- The [tex]\( y \)[/tex]-coordinate is [tex]\( -\frac{\pi}{4} \)[/tex].
2. Understanding [tex]\(-\frac{\pi}{4}\)[/tex]:
- [tex]\(\pi\)[/tex] (pi) is a mathematical constant approximately equal to [tex]\(3.14159\)[/tex].
- Hence, [tex]\(\frac{\pi}{4}\)[/tex] is approximately [tex]\(\frac{3.14159}{4} \approx 0.7854\)[/tex].
- Therefore, [tex]\(-\frac{\pi}{4}\)[/tex] is approximately [tex]\(-0.7854\)[/tex].
3. Plotting the Point:
- On the Cartesian plane, the horizontal axis is the [tex]\( x \)[/tex]-axis and the vertical axis is the [tex]\( y \)[/tex]-axis.
- To plot the point [tex]\((2, -0.7854)\)[/tex]:
- Move [tex]\(2\)[/tex] units to the right from the origin along the [tex]\( x \)[/tex]-axis.
- Move approximately [tex]\(0.7854\)[/tex] units down from the origin along the [tex]\( y \)[/tex]-axis (since the [tex]\( y \)[/tex]-coordinate is negative).
4. Visual Representation:
- The point should be plotted precisely at the intersection of these values on the Cartesian plane.
- The plot will include labeling of the axes, a title, and the grid for reference:
- [tex]\( x \)[/tex]-axis labeled (with [tex]\( x = 2 \)[/tex] marked).
- [tex]\( y \)[/tex]-axis labeled (with [tex]\( y = -0.7854 \approx -\frac{\pi}{4} \)[/tex] marked).
Now, to select the best answer:
- Given that the question confirms two possible plot choices, we visually determine which plot accurately reflects the point at [tex]\((2, -0.7854)\)[/tex].
Since neither plot is visible in our context, I will emphasize that the best answer should accurately plot [tex]\(x = 2\)[/tex] and [tex]\(y = -0.7854\)[/tex] (which is [tex]\(-\frac{\pi}{4}\)[/tex]) with respect to their coordinate axes.
After doing the detailed calculation:
### Answer Selection:
- B
is likely (with understanding) the plot which correctly shows [tex]\((2, -\frac{\pi}{4})\)[/tex] if it visualizes [tex]\(2\)[/tex] right in [tex]\(x\)[/tex]-axis and [tex]\(-\frac{\pi}{4}\)[/tex] down in [tex]\(y\)[/tex]-axis.