Suppose [tex]$A$[/tex] and [tex]$B$[/tex] are dependent events. If [tex]$P(A)=0.5$[/tex] and [tex]$P(B \mid A)=0.6$[/tex], what is [tex][tex]$P(A \cap B)$[/tex][/tex]?

A. 0.5
B. 0.1
C. 0.6
D. 0.3



Answer :

To determine the probability of both events [tex]\( A \)[/tex] and [tex]\( B \)[/tex] occurring together, [tex]\( P(A \cap B) \)[/tex], for dependent events, we use the definition of conditional probability.

The formula for the probability of the intersection of two dependent events is given by:

[tex]\[ P(A \cap B) = P(A) \times P(B \mid A) \][/tex]

Here, we are given:
- [tex]\( P(A) = 0.5 \)[/tex]
- [tex]\( P(B \mid A) = 0.6 \)[/tex]

Substituting these values into the formula, we get:

[tex]\[ P(A \cap B) = 0.5 \times 0.6 \][/tex]

Now, multiplying these together:

[tex]\[ P(A \cap B) = 0.3 \][/tex]

Therefore, the probability that both events [tex]\( A \)[/tex] and [tex]\( B \)[/tex] occur is [tex]\( 0.3 \)[/tex].

So the correct answer is

[tex]\[ \boxed{0.3} \][/tex]
which corresponds to option [tex]\( D \)[/tex].