Predict the general term, or [tex]$n$[/tex]th term, [tex]$a_n$[/tex], of the sequence.

[tex]\[
\begin{array}{l}
-12, 48, -192, 768, -3072, \ldots \\
a_n = \square
\end{array}
\][/tex]

(Simplify your answer.)



Answer :

To find the general term, [tex]\( a_n \)[/tex], of the given sequence:
[tex]\[ -12, 48, -192, 768, -3072, \ldots \][/tex]

we proceed as follows:

1. Identify the first term [tex]\( a_1 \)[/tex]:
The first term of the sequence is [tex]\( a_1 = -12 \)[/tex].

2. Determine the common ratio [tex]\( r \)[/tex]:
To find the common ratio, we divide the second term by the first term:
[tex]\[ r = \frac{48}{-12} = -4 \][/tex]
We can double-check this by considering the third and second terms:
[tex]\[ r = \frac{-192}{48} = -4 \][/tex]

3. Form the general term:
In a geometric sequence, the general term [tex]\( a_n \)[/tex] can be expressed as:
[tex]\[ a_n = a_1 \cdot r^{n-1} \][/tex]
Substituting the values of [tex]\( a_1 \)[/tex] and [tex]\( r \)[/tex]:
[tex]\[ a_n = -12 \cdot (-4)^{n-1} \][/tex]

Thus, the general term [tex]\( a_n \)[/tex] of the sequence is:
[tex]\[ \boxed{a_n = -12 \cdot (-4)^{n-1}} \][/tex]