Answer :
First, let's establish the data we have and correct any typos for clarity:
We have record counts divided by gender (male and female) and two height categories: "Over 6" and "Under 6." The table provided appears to have an unclear structure, so let’s re-organize the data into a more readable and complete table.
Given data:
- Male, Over 6: 86
- Male, Under 6: 12
- Female, Under 6: 8
Assuming the missing cell is for "Female, Over 6," we need to calculate its value such that the total count remains 200.
### Step-by-Step Solution:
#### Step 1: Define Known Values
Here’s the assumed rectified table:
[tex]\[ \begin{array}{|c|c|c|} \hline & \text{Over 6} & \text{Under 6} \\ \hline \text{Male} & 86 & 12 \\ \hline \text{Female} & x & 8 \\ \hline \end{array} \][/tex]
#### Step 2: Calculate Total Counts for Each Category
From the initial values, we calculate the total number of males and females, and also the totals for each height category.
- Total for Over 6: [tex]\(86\)[/tex] (Male Over 6) [tex]\( + x \)[/tex] (Female Over 6)
- Total for Under 6: [tex]\(12\)[/tex] (Male Under 6) [tex]\( + 8 \)[/tex] (Female Under 6)
- Total males: [tex]\(86 + 12 = 98\)[/tex]
- Total females: [tex]\(x + 8\)[/tex]
#### Step 3: Ensure Consistency with Total Population
The total population is 200, so:
[tex]\[ 98 \text{ (Total Males)} + (x + 8) \text{ (Total Females)} = 200 \][/tex]
This simplifies to:
[tex]\[ x + 106 = 200 \][/tex]
[tex]\[ x = 94 \][/tex]
Thus, the number of females over 6 must be 94.
#### Step 4: Complete the Table
Here is the completed two-way frequency table with marginal frequencies:
[tex]\[ \begin{array}{|c|c|c|c|} \hline & \text{Over 6} & \text{Under 6} & \text{Total} \\ \hline \text{Male} & 86 & 12 & 98 \\ \hline \text{Female} & 94 & 8 & 102 \\ \hline \text{Total} & 180 & 20 & 200 \\ \hline \end{array} \][/tex]
#### Verification of Marginal Frequencies:
- Total Over 6: [tex]\(86\)[/tex] (Male) + [tex]\(94\)[/tex] (Female) = [tex]\(180\)[/tex]
- Total Under 6: [tex]\(12\)[/tex] (Male) + [tex]\(8\)[/tex] (Female) = [tex]\(20\)[/tex]
- Total Males: [tex]\(98\)[/tex]
- Total Females: [tex]\(102\)[/tex]
- Population Total: [tex]\(200\)[/tex]
This finalized table and the marginal frequencies correctly show the frequency distribution of the population divided by gender and height categories.
We have record counts divided by gender (male and female) and two height categories: "Over 6" and "Under 6." The table provided appears to have an unclear structure, so let’s re-organize the data into a more readable and complete table.
Given data:
- Male, Over 6: 86
- Male, Under 6: 12
- Female, Under 6: 8
Assuming the missing cell is for "Female, Over 6," we need to calculate its value such that the total count remains 200.
### Step-by-Step Solution:
#### Step 1: Define Known Values
Here’s the assumed rectified table:
[tex]\[ \begin{array}{|c|c|c|} \hline & \text{Over 6} & \text{Under 6} \\ \hline \text{Male} & 86 & 12 \\ \hline \text{Female} & x & 8 \\ \hline \end{array} \][/tex]
#### Step 2: Calculate Total Counts for Each Category
From the initial values, we calculate the total number of males and females, and also the totals for each height category.
- Total for Over 6: [tex]\(86\)[/tex] (Male Over 6) [tex]\( + x \)[/tex] (Female Over 6)
- Total for Under 6: [tex]\(12\)[/tex] (Male Under 6) [tex]\( + 8 \)[/tex] (Female Under 6)
- Total males: [tex]\(86 + 12 = 98\)[/tex]
- Total females: [tex]\(x + 8\)[/tex]
#### Step 3: Ensure Consistency with Total Population
The total population is 200, so:
[tex]\[ 98 \text{ (Total Males)} + (x + 8) \text{ (Total Females)} = 200 \][/tex]
This simplifies to:
[tex]\[ x + 106 = 200 \][/tex]
[tex]\[ x = 94 \][/tex]
Thus, the number of females over 6 must be 94.
#### Step 4: Complete the Table
Here is the completed two-way frequency table with marginal frequencies:
[tex]\[ \begin{array}{|c|c|c|c|} \hline & \text{Over 6} & \text{Under 6} & \text{Total} \\ \hline \text{Male} & 86 & 12 & 98 \\ \hline \text{Female} & 94 & 8 & 102 \\ \hline \text{Total} & 180 & 20 & 200 \\ \hline \end{array} \][/tex]
#### Verification of Marginal Frequencies:
- Total Over 6: [tex]\(86\)[/tex] (Male) + [tex]\(94\)[/tex] (Female) = [tex]\(180\)[/tex]
- Total Under 6: [tex]\(12\)[/tex] (Male) + [tex]\(8\)[/tex] (Female) = [tex]\(20\)[/tex]
- Total Males: [tex]\(98\)[/tex]
- Total Females: [tex]\(102\)[/tex]
- Population Total: [tex]\(200\)[/tex]
This finalized table and the marginal frequencies correctly show the frequency distribution of the population divided by gender and height categories.