Assume that the significance level is [tex]\alpha = 0.1[/tex]. Use the given statement to find the [tex]P[/tex]-value and the critical value(s).

The test statistic of [tex]z = -1.71[/tex] is obtained when testing the claim that [tex]p = \frac{1}{5}[/tex].

- [tex]P[/tex]-value = [tex]\square[/tex] (Round to four decimal places as needed.)
- The critical value(s) is/are [tex]\square[/tex] (Round to two decimal places as needed. Use a comma to separate answers as needed.)



Answer :

Let's break down the solution step-by-step:

1. Identify the parameters:
- Significance level [tex]\(\alpha = 0.1\)[/tex].
- Test statistic [tex]\(z = -1.71\)[/tex].

2. Finding the P-value:
The P-value is the probability that the observed statistic is at least as extreme as the test statistic, given that the null hypothesis is true. Since we are using a [tex]\(z\)[/tex]-test, we will use the cumulative distribution function (CDF) of the standard normal distribution.

- For a [tex]\(z\)[/tex]-value of [tex]\(-1.71\)[/tex], we need to find the cumulative probability to the left of [tex]\(z = -1.71\)[/tex] in the standard normal distribution.

The P-value rounded to four decimal places is:
[tex]\[ \boxed{0.0436} \][/tex]

3. Finding the critical values:
Since we are given a significance level [tex]\(\alpha = 0.1\)[/tex] for a two-tailed test, we will split this [tex]\(\alpha\)[/tex] into two tails, with each tail getting [tex]\(\alpha/2 = 0.05\)[/tex].

- We need to find the z-scores that correspond to the cumulative probabilities of [tex]\(0.05\)[/tex] and [tex]\(1 - 0.05 = 0.95\)[/tex] in the standard normal distribution.

The critical values, rounded to two decimal places, are:
[tex]\[ \boxed{-1.64, 1.64} \][/tex]

In conclusion:

- The P-value is [tex]\( \boxed{0.0436} \)[/tex].
- The critical values are [tex]\( \boxed{-1.64, 1.64} \)[/tex].

These computations align with the necessary steps for understanding hypothesis testing using the normal distribution.