Multiply across the top of the unit conversion. What is the product of the numerator?

[tex]\[
\begin{array}{l|l}
24 \text{ moles } C_2H_6 & 7 \text{ moles } O_2 \\
\hline & 2 \text{ moles } C_2H_6
\end{array}
\][/tex]

Do not round the answer.



Answer :

Let's solve the problem step-by-step:

1. Identify the given units and values:
- We have [tex]\(24 \text { moles of } C_2H_6\)[/tex] in the numerator.
- We have [tex]\(2 \text { moles of } C_2H_6\)[/tex] in the denominator.

2. Set up the division:
- We need to find the product by dividing the numerator value by the denominator value:

[tex]\[ \frac{24 \text { moles } C_2H_6}{2 \text { moles } C_2H_6} \][/tex]

3. Perform the division:
- Divide [tex]\(24\)[/tex] by [tex]\(2\)[/tex]:

[tex]\[ \frac{24}{2} = 12 \][/tex]

Therefore, the product of the numerator is [tex]\(12.0\)[/tex], which is already the simplified result without rounding.