To solve this problem, we need to analyze the possible outcomes when a coin is tossed three times and identify those outcomes where "at least two heads" occur.
Firstly, we'll list all the possible outcomes when a coin is tossed three times:
1. HHH
2. HHT
3. HTH
4. HTT
5. THH
6. THT
7. TTH
8. TTT
Next, we need to count the number of heads in each outcome to determine which ones satisfy the condition of having "at least two heads." Let's check each one:
1. HHH - 3 heads
2. HHT - 2 heads
3. HTH - 2 heads
4. HTT - 1 head
5. THH - 2 heads
6. THT - 1 head
7. TTH - 1 head
8. TTT - 0 heads
We are only interested in the outcomes with at least two heads. From the list above, the outcomes that meet this criterion are:
1. HHH
2. HHT
3. HTH
4. THH
Thus, these four outcomes would be included in the compound event "at least two heads."
Given the possible answer choices:
- A. HTT
- B. THH
- C. THT
- D. TTH
Let's identify which of these matches our list of valid outcomes:
- HTT: 1 head (Not included)
- THH: 2 heads (Included)
- THT: 1 head (Not included)
- TTH: 1 head (Not included)
Therefore, the correct answer is B. THH, as it is the outcome from the choices that satisfies the condition of having at least two heads.
